81k^4+12k^2+108k+32=0

来源:百度知道 编辑:UC知道 时间:2024/09/21 15:29:34
求k的值
急~

假设方程形如:(9k^2加b)^2加c(y^2加d)^2=0待定系数:18b加c=12,2cd=108,cd^2=32自己解

>> solve('81*k^4+12*k^2+108*k+32=0')

ans =

[ 1/18*2^(1/2)*((-4*(53873+9*27757137^(1/2))^(1/3)+(53873+9*27757137^(1/2))^(2/3)+868)/(53873+9*27757137^(1/2))^(1/3))^(1/2)+1/18*i*((16*(53873+9*27757137^(1/2))^(1/3)*((-4*(53873+9*27757137^(1/2))^(1/3)+(53873+9*27757137^(1/2))^(2/3)+868)/(53873+9*27757137^(1/2))^(1/3))^(1/2)+2*((-4*(53873+9*27757137^(1/2))^(1/3)+(53873+9*27757137^(1/2))^(2/3)+868)/(53873+9*27757137^(1/2))^(1/3))^(1/2)*(53873+9*27757137^(1/2))^(2/3)+1736*((-4*(53873+9*27757137^(1/2))^(1/3)+(53873+9*27757137^(1/2))^(2/3)+868)/(53873+9*27757137^(1/2))^(1/3))^(1/2)+972*2^(1/2)*(53873+9*27757137^(1/2))^(1/3))/(53873+9*27757137^(1/2))^(1/3)/((-4*(53873+9*27757137^(1/2))^(1/3)+(53873+9*27757137^(1/2))^(2/3)+868)/(53873+9*27757137^(1/2))^(1/3))^(1/2))^(1/2)]
[ 1/18*2^(1/2)*((-4*(53873+9*27757137^(1/2))^(1/3)+(53873+9*27757137^(1/2))^(2/3)+868)/(53873+9*27757137^(1/2))^(